You have three dice loaded so that the number 6 is n times as likely to come up as all of the other numbers individually. (That is, the respective individual odds of each of the 6 numbers coming up are 1, 1, 1, 1, 1, n for the faces 1-6 respectively.) Express in terms of n the probability that two of the three dice will show the same number while the third die shows a different number.
And remember folks: Math is #
(infinity)
E (1/(2^k))
k=1
“I’m a stupid fatty and I love to play with my Easy Bake oven!â€