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Author Topic: Mario Fallout Shelter  (Read 41772 times)

« Reply #120 on: May 11, 2003, 10:45:47 AM »
There is a serious answer. If no one comes up with anything by some time later I'll probably explain *IT* late today.

"I''m a stupid fatty and I love to play with my Easy Bake oven!"

Insane Steve

  • Professional Cynic
« Reply #121 on: May 11, 2003, 01:12:15 PM »
I've got another idea.

e^0 = 1, so:

e^(2(pi)i)_____ e^0

Taking the natural log of both sides yields

2(pi)i_____0

This is where it gets interesting. If you multiply out 2(pi)i, you get about sqrt -40.

SO:

sqrt -40 ____ 0

This is where it gets interesting. If you divide both sides by sqrt -40, you get:

1 _____ 0, so it would be >. But

squaring both sides yields

-40 ______ 0, so this would be <.

I'll go with > though, as -4<3, but -4^2>3^2.

Congratulations! You have just been blessed by the wisdom of Steve.
~I.S.~

« Reply #122 on: May 11, 2003, 09:53:32 PM »
Nah, nice try but it's way more complicated.
I don't know how much you know about calculus, but...

Start with  z = cos(x) + i*sin(x)    ......(1)

     Then  dz/dx = -sin(x) + i*cos(x)

                 = i(cos(x) + i*sin(x))         (since i^2 = -1)

                 = i*z

       So   dz/z = i*dx


Now integrate both sides

               ln(z) = i*x + c    From (1); when x=0, z=1   so c=0

               ln(z) = i*x

                   z = e^(i*x)    but z = cos(x) + i*sin(x), So

   cos(x) + i*sin(x) = e^(i*x)       ......(2)

Put x = pi in (2) and we get:

        -1 + 0 = e^(i*pi)

and so     e^(i*pi) + 1 = 0

e^(i*pi) = -1

Square both sides for      e^(2*i*pi) = 1

And so, gentle reader, e^(2*pi*i)=.999...=1

"I''m a stupid fatty and I love to play with my Easy Bake oven!"

Sapphira

  • Inquiring
« Reply #123 on: May 11, 2003, 10:01:18 PM »
You're both freaks.

--------------------
If things don''t go your way, just keep complaining until your dreams come true.
"The surest way to happiness is to lose yourself in a cause greater than yourself."

Chupperson Weird

  • Not interested.
« Reply #124 on: May 11, 2003, 10:46:34 PM »
Sapphira, if you don't want to read it, you don't have to.
That was a joke.

Sapphira

  • Inquiring
« Reply #125 on: May 12, 2003, 07:08:27 AM »
I'm not reading it. I'm just skipping over it, hoping that this place will go back to having a *normal* conversation.

--------------------
If things don''t go your way, just keep complaining until your dreams come true.
"The surest way to happiness is to lose yourself in a cause greater than yourself."

Insane Steve

  • Professional Cynic
« Reply #126 on: May 12, 2003, 07:02:52 PM »
Condisering that I'm only in Algebra II and know NOTHING about Calculus, I really didn't know how to do that. I just had to go along with the old Algebra methods I learned. Although I really can't see the flaw in that work... Ah well.

This is kind of more a math puzzle...

You have a regular hexagon. Place 6 integers, one on each vertex, so that the value on each vertex is equal to the absolute value of the difference of the two surrounding vertices, and the 6 integers add up to a total of 100.

And oh yeah, none of the integers can be negative.

Congratulations! You have just been blessed by the wisdom of Steve.
~I.S.~

« Reply #127 on: May 12, 2003, 07:10:11 PM »
okay smart guys, if there are three apples, and you take two how many do you have?

\
\\  __
\\\(^^) Rollin,Rollin,Rollin

Guns dont kill people, I kill people
------------------------------
Some things are good left unsaid. This may be one of them...

Insane Steve

  • Professional Cynic
« Reply #128 on: May 12, 2003, 07:16:51 PM »
Erm... you have two apples if you take two. So yea.

Really good mathematicians (Lizard Dude or CashCrazed) may want to try my hexagon problem. Others may go for this one.

There are 4 blackbirds on a fence. You shoot one. How many are left on the fence?

Congratulations! You have just been blessed by the wisdom of Steve.
~I.S.~

Sapphira

  • Inquiring
« Reply #129 on: May 12, 2003, 07:21:25 PM »
Heheh. I know this one. This is one of the questions from the Un-telligent test. Sad if anyone gets it wrong. I have to see this. :)

Here's another one. (Not from that test.)
Do they have a 4th of July in England?

--------------------
If things don''t go your way, just keep complaining until your dreams come true.
"The surest way to happiness is to lose yourself in a cause greater than yourself."

Insane Steve

  • Professional Cynic
« Reply #130 on: May 12, 2003, 07:24:50 PM »
Of course! Not like they do anything special on it, but they do.

Congratulations! You have just been blessed by the wisdom of Steve.
~I.S.~

« Reply #131 on: May 12, 2003, 07:26:08 PM »
Hello, I have just escaped the radiation. Yes, Sapphira, it's right after the 3rd of July. Anyhow, let's play a Mario NGC game to pass the time!

Another moment and it would have been... later.

Sapphira

  • Inquiring
« Reply #132 on: May 12, 2003, 07:31:41 PM »


Edited by - Sapphira on 5/12/2003 9:47:26 PM
"The surest way to happiness is to lose yourself in a cause greater than yourself."

Sapphira

  • Inquiring
« Reply #133 on: May 12, 2003, 07:32:47 PM »
Oh yeah, and, Wheel_Kirby, I believe the question should've been worded:
If there are 3 apples, and you take 2 away, how many do you have?

Oh, and as for the Un-telligence test, I was laughing my head off; my brother missed the question on how the coin would land! Hahahaha!!! ...Okay, sorry. He also said he'd beat the living [urine] out of his friend on the question with that option. Such class. Not exactly the shiniest penny in the fountain...

--------------------
If things don''t go your way, just keep complaining until your dreams come true.
"The surest way to happiness is to lose yourself in a cause greater than yourself."

« Reply #134 on: May 12, 2003, 09:57:29 PM »
No, that was my question, and yes the answer is two, because you have what you take, and I have many many many more...;-)


\
\\  __
\\\(^^) Rollin,Rollin,Rollin

Guns dont kill people, I kill people
------------------------------
Some things are good left unsaid. This may be one of them...

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