Ah, this is what's funny. That one is <, as 2 is less than 3. For the first one, 3=3.
For 2+2 = cube root of 8, 2+2 has 3 solutions: 4, 10 (Base 4), and 11 (Base 3). Cube root of 8 has three solutions: 2, -1 + (i)sqrt 3, -1 - (i)sqrt 3. We need not worry about bases here, as we are not working with numbers greater than 8.
For 1+1 < cube root of 2, 1+1 can only have 2 solutions: 2, and 10 in base 2. However, cube root of 2 has 3 solutions: 2^1/3, and 2 other imaginary conjugates. And if there are bases to worry abuot, that given even more solutions to the cube root of 2.
Thus, Solutions of 1+1 < solutions of cube root of 2.
Congratulations! You have just been blessed by the wisdom of Steve.